Question

Какой объем кислорода потребуется при взаимодействии серы массой 16 г, если в результате реакции образуется SO3

Answer 1

Дано:
m(S) = 16 г
Найти: V (O2)
Решение:

$3O_{2} + 2S = 2SO_{3}$

(Под кислородом напишите 3 моль, под серой 2 моль. Из-за коэффициентов.)

M(S) = 32 г/моль
M(O2) = 16 * 2 = 32 г/моль

n = m/M
n(S) = 16/32 = 0,5 моль

(Теперь в уравнении напишите над серой 0,5 моль, а над кислородом x моль)
Составляем пропорцию:
$\frac{x}{3} = \frac{0,5}{2}$
Где x = n(O2) = 0,5 * 3/2 = 0,75 МОЛЬ
V=Vm * n
V(O2) = 22,4 л/моль * 0,75 = 16,8 л
Ответ: V(O2) = 16,8 л

Answer 2

Oxygen Volume Required for Sulfur Reaction to Form SO3

When sulfur with a mass of 16 g reacts to form SO3, the volume of oxygen required can be calculated using the molar ratio of sulfur and oxygen in the balanced chemical equation for the reaction.

The balanced chemical equation for the reaction of sulfur to form SO3 is:

S(s) + O2(g) → SO3(g)

From the balanced chemical equation, it can be inferred that 1 mole of sulfur reacts with 1 mole of oxygen to produce 1 mole of SO3.

To calculate the volume of oxygen required, we can use the ideal gas law, which states that at standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters.

Using the molar mass of sulfur (S = 32 g/mol) and the given mass of sulfur (16 g), we can calculate the number of moles of sulfur. Then, based on the balanced chemical equation, we can determine the volume of oxygen required.

The calculation can be expressed as follows:

Given: - Mass of sulfur (S) = 16 g - Molar mass of sulfur (S) = 32 g/mol

Calculation: 1. Calculate the number of moles of sulfur: - Number of moles = Mass / Molar mass - Number of moles of sulfur = 16 g / 32 g/mol = 0.5 moles

2. Determine the volume of oxygen required based on the molar ratio: - From the balanced chemical equation: 1 mole of S reacts with 1 mole of O2 - Since 1 mole of any gas occupies 22.4 liters at STP, the volume of oxygen required = 0.5 moles * 22.4 L/mole = 11.2 liters

Answer: The volume of oxygen required for the reaction of 16 g of sulfur to form SO3 is 11.2 liters at standard temperature and pressure (STP).

This calculation is based on the molar ratio and the ideal gas law, providing an accurate estimation of the volume of oxygen required for the given reaction.