Question

Для получения висмута нитрата основного, применяемого в медицине в качестве вяжущего и антисептического средства при желудочно-кишечных расстройствах, используют природные минералы висмутин (Bi2S3) и бисмит (Bi2O3). Рассчитайте массу атомарного висмута (кг) в образце породы массой 5,5 кг, содержащей 75% Bi2S3 и 25% Bi2O3 . Ответ округлите до тысячных. ПЖЖЖЖ ОТВЕТЬ БЫСТРО ОЧЕНЬ НУЖНО ДАМ 40 БАЛЛОВ

Answer 1

Ответ:

4,587 кг Bi

Объяснение:

Массовая доля висмута в висмутине Bi2S3 равна 209*2/(209*2 + 32*3) = 0,8132.

Массовая доля висмута в бисмите Bi2O3 равна 209*2/(209*2 + 16*3) = 0,897.

Тогда масса атомарного висмута (кг) в образце породы составит 5,5*0,75*0,8132 + 5,5*0,25*0,897 = 4, 587 кг. (в округлении до тысячных)

Answer 2

To calculate the mass of atomic bismuth (in kilograms) in a sample of rock weighing 5.5 kg and containing 75% Bi2S3 and 25% Bi2O3, we can follow these steps:

1. Calculate the mass of Bi2S3 in the sample: - Mass of Bi2S3 = 75% of 5.5 kg = 0.75 * 5.5 kg = 4.125 kg

2. Calculate the mass of Bi2O3 in the sample: - Mass of Bi2O3 = 25% of 5.5 kg = 0.25 * 5.5 kg = 1.375 kg

3. Calculate the molar mass of Bi2S3 and Bi2O3: - Molar mass of Bi2S3 = (2 * atomic mass of Bi) + (3 * atomic mass of S) - Molar mass of Bi2O3 = (2 * atomic mass of Bi) + (3 * atomic mass of O)

According to the periodic table, the atomic mass of bismuth (Bi) is approximately 208.98 g/mol, and the atomic mass of sulfur (S) is approximately 32.06 g/mol. The atomic mass of oxygen (O) is approximately 16.00 g/mol.

- Molar mass of Bi2S3 = (2 * 208.98 g/mol) + (3 * 32.06 g/mol) = 514.14 g/mol - Molar mass of Bi2O3 = (2 * 208.98 g/mol) + (3 * 16.00 g/mol) = 465.96 g/mol

4. Calculate the number of moles of Bi2S3 and Bi2O3: - Number of moles of Bi2S3 = Mass of Bi2S3 / Molar mass of Bi2S3 - Number of moles of Bi2O3 = Mass of Bi2O3 / Molar mass of Bi2O3

- Number of moles of Bi2S3 = 4.125 kg / 0.51414 kg/mol ≈ 8.02 mol - Number of moles of Bi2O3 = 1.375 kg / 0.46596 kg/mol ≈ 2.95 mol

5. Calculate the mass of atomic bismuth (Bi): - Mass of atomic bismuth (Bi) = (Number of moles of Bi2S3 * 2 * atomic mass of Bi) + (Number of moles of Bi2O3 * 2 * atomic mass of Bi)

- Mass of atomic bismuth (Bi) = (8.02 mol * 2 * 208.98 g/mol) + (2.95 mol * 2 * 208.98 g/mol) ≈ 3,482.35 g ≈ 3.482 kg

Therefore, the mass of atomic bismuth (Bi) in the given sample of rock is approximately 3.482 kilograms.

Please note that the answer has been rounded to the nearest thousandth as requested.