Question

Во сколько раз изменится скорость прямой и обратной реакций, протекающих в гомогенной системе 2CL2+2H2O(г)=4HCL+O2, если увеличить давление в системе в 3 раза? Считать, что количество реагирующих веществ и температура те же, что в начальном состоянии.

Answer 1

Увеличить давление в 3 раза = увеличить концентрации в 3 раза:
u = Kпр*c(Cl2)^2*c(H2O)^2
u = Kпр*(3Cl2)^2*(3H2O)^2 = 81
Увеличится в 81 раз
Обратная реакция:
uобр = kобр*(HCl)^4*(O2)
uобр = kобр*(3HCl)^4 *(4O2) = 324
Увеличится в 324 раза о.о

Answer 2

Answer:

To calculate the change in the speed of the forward and reverse reactions when the pressure in the system is increased by 3 times, we can use the concept of Le Chatelier's principle. According to Le Chatelier's principle, if a system at equilibrium is disturbed by a change in pressure, temperature, or concentration of reactants or products, the system will shift its position of equilibrium to counteract the effect of the disturbance.

Calculation:

The change in pressure will affect the equilibrium of the reaction. In this case, the reaction is: 2Cl2 (g) + 2H2O (g) ⇌ 4HCl + O2

When the pressure is increased by 3 times, the system will shift to counteract the effect of the disturbance. Since the number of moles of gas changes in this reaction, the equilibrium will shift to balance the pressure change.

According to the reaction, there are 4 moles of gas on the left side and 5 moles of gas on the right side. Therefore, increasing the pressure will cause the equilibrium to shift to the side with fewer moles of gas to counteract the pressure increase.

Conclusion:

The speed of the forward and reverse reactions will change in such a way that the equilibrium will shift to reduce the effect of the increased pressure. The exact change in the speed of the reactions can be calculated using the principles of chemical equilibrium and Le Chatelier's principle.