Question

Задача. Елемент має вищий оксид складу ЕО3. Масова частка елемента в сполуці з Гідрогеном дорівнює 98, 46%. Укажіть число нейтронів у ядрі атома цьго елемента. Вправа. Вказати тип елемента ( s , p, d, f): а)Рубідій; б) Нобелій; в) Купрум; г) Бор. Для елемента г) запишіть електронну та графічну формули.

Answer 1

Task 1: Finding the number of neutrons in an element with the formula EO3 and a mass fraction of 98.46% with hydrogen.

To find the number of neutrons in an element with the formula EO3 and a mass fraction of 98.46% with hydrogen, we need to determine the atomic number and mass number of the element.

The atomic number of an element corresponds to the number of protons in its nucleus. Since the formula EO3 indicates that there are three oxygen atoms (O) in the compound, the atomic number of oxygen is 8.

The mass number of an element corresponds to the sum of protons and neutrons in its nucleus. To find the mass number, we need to know the atomic mass of the element. However, the information provided in the question does not include the atomic mass.

Without the atomic mass, it is not possible to determine the number of neutrons in the element accurately. The atomic mass can vary depending on the isotope of the element. Isotopes have the same number of protons but different numbers of neutrons.

Therefore, we cannot determine the number of neutrons in the element without additional information.

Task 2: Determining the type of element for Rubidium, Nobelium, Copper, and Boron.

a) Rubidium: Rubidium (Rb) belongs to the s-block of the periodic table. It is an alkali metal.

b) Nobelium: Nobelium (No) belongs to the f-block of the periodic table. It is a synthetic element and a member of the actinide series.

c) Copper: Copper (Cu) belongs to the d-block of the periodic table. It is a transition metal.

d) Boron: Boron (B) belongs to the p-block of the periodic table. It is a metalloid.

Task 3: Writing the electron and graphical formulas for Boron (B).

The electron configuration of Boron (B) is 1s^2 2s^2 2p^1.

The graphical formula for Boron (B) is:

  B

I hope this helps! Let me know if you have any further questions.