Question

Решите Пожалуйста!Очень надо!!!!! Приготовили 80гр. 10% раствора соли. Добавили: а)соли 30гр. б) воды 60гр. в) 40гр. 50% раствора _____________ Найти: массу р-ра, Объём воды.

Answer 1

M(соли) = ω*m(p-pa) = 0,1*80 г. = 8 г.
1) + 30 г. соли
ω(соли) = (8г. + 30г) : (80 г.+ 30 г.) = 0,345 или 34,5%
m(p-pa) = 30г. + 80 г. = 110г.
m(H₂O) = 110 г.- 38 г. =  72 г.
V(H₂O) = m/p = 72 г : 1,0 г/мль = 72 мл
2)  + 60 г. воды
ω(соли) = 8 г./(80г. + 60 г.) = 0,057 или 5,7%
m(p-pa) = 80 г. + 60 г. = 140 г. 
m(H₂O) = 140 г. - 8г. = 132г.
V(H₂O) = 132 г. /1,0 г/мл = 132 мл
3) + 40 г 50% раствора
 m₂(соли) = ω₂*m₂(p-pa) = 0,5*40 г. = 20 г.
 m₃(cоли) = 8 г. + 20 г. = 28 г.
 ω₃(соли) = (8г.+ 20г.)/(80г. + 40 г.)= 0,233 или 23,3%
m(p-pa) = 80 г. + 40 г. + 120 г.
m(H₂O) = 120 г. - 8г. - 20 г. = 92 г.
V(H₂O) = 92 г./1,0 г/мл = 92 мл.
   
 

Answer 2

Problem Analysis

To solve this problem, we need to find the mass of the resulting solution and the volume of water added. We are given the following information: - Initial solution: 80g of a 10% salt solution - Added components: a) 30g of salt b) 60g of water c) 40g of a 50% salt solution

We need to determine the mass of the resulting solution and the volume of water added.

Solution

To find the mass of the resulting solution, we need to add up the masses of all the components. Let's calculate it step by step:

1. Initial solution: 80g of a 10% salt solution - The initial solution contains 10% salt, which means that 10% of the solution's mass is salt. - Therefore, the mass of salt in the initial solution is 10% of 80g, which is 8g.

2. Added components: a) 30g of salt b) 60g of water c) 40g of a 50% salt solution - The 50% salt solution contains 50% salt, which means that 50% of its mass is salt. - Therefore, the mass of salt in the 50% salt solution is 50% of 40g, which is 20g.

Now, let's calculate the total mass of the resulting solution: - Mass of the initial solution: 80g - Mass of added salt: 8g + 30g + 20g = 58g - Mass of added water: 60g

Therefore, the mass of the resulting solution is 80g + 58g + 60g = 198g.

To find the volume of water added, we need to consider that the density of water is 1g/mL. Since the mass of water added is 60g, the volume of water added is also 60 mL.

Summary

Based on the given information, the mass of the resulting solution is 198g, and the volume of water added is 60 mL.

Please let me know if you need any further assistance!