Question

Химия - 100 баллов. 1. Как превратить 75% раствор уксусный кислоты в 3%? 2. Как получить 5% раствор гидроксида натрия из 2% и 10%? Подробный ответ.​

Answer 1

Рассчитываем на А мл раствора. В нем (0,75*А) мл уксуса. Надо, чтобы это было 3% в новом растворе. Вот пропорция: (0,75*А) мл — 3 % Х мл раствор — 100 % Х= 0,75*А*100/3 = 25А. 25А — А= 24А. Получаем 1:24. То есть на столовую ложку раствора надо добавить не 12, а 24 ложек воды

Answer 2

How to convert a 75% acetic acid solution to a 3% solution?

To convert a 75% acetic acid solution to a 3% solution, you will need to dilute the original solution with a suitable solvent, such as water. The dilution formula can be used to calculate the amount of the original solution and the solvent needed.

The formula for dilution is:

C1V1 = C2V2

Where: - C1 is the initial concentration of the solution (75%) - V1 is the volume of the initial solution - C2 is the final concentration of the solution (3%) - V2 is the final volume of the solution

To solve for V2, we can rearrange the formula as:

V2 = (C1V1) / C2

Substituting the given values:

V2 = (75% * V1) / 3%

Now, we need to find the value of V1, the volume of the initial solution. This can be calculated by subtracting the final volume (V2) from the initial volume (V1).

Let's assume we want to prepare 100 mL of the 3% acetic acid solution.

V2 = 100 mL

Substituting this value into the formula:

100 mL = (75% * V1) / 3%

Now, we can solve for V1:

V1 = (100 mL * 3%) / 75%

Calculating this:

V1 = (100 mL * 0.03) / 0.75

V1 = 4 mL

Therefore, to prepare a 3% acetic acid solution from a 75% solution, you would need to mix 4 mL of the 75% solution with 96 mL of water.