Question

напишите молекулярные и ионные уравнения реакций, протекающих при сливании растворов: нитрата серебра фосфата калия, гидроксида натрия и фосфорной кислоты.

Answer 1

Ответ:

Объяснение:

3AgNO3 + K3PO4 = 3KNO3 + Ag3PO4↓

3Ag(+) + 3NO3(-) + 3K(+) + PO4(3-) = 3K(+) + 3NO3(-) + Ag3PO4↓

3Ag(+) + PO4(3-) = Ag3PO4↓

3NaOH + H3PO4 = Na3PO4 + 3H2O

3Na(+) + 3OH(-) + 3H(+) + PO4(3-) = 3Na(+) + PO4(3-) + 3H2O

H(+) + OH(-) = H2O

Answer 2

Molecular and Ionic Equations for the Reaction of Silver Nitrate with Potassium Phosphate:

The reaction between silver nitrate (AgNO3) and potassium phosphate (K3PO4) can be represented by the following molecular equation:

AgNO3 + K3PO4 → Ag3PO4 + KNO3

To write the ionic equation, we need to break down the reactants and products into their respective ions:

AgNO3 dissociates into Ag+ and NO3- ions. K3PO4 dissociates into 3K+ and PO4^3- ions. Ag3PO4 dissociates into 3Ag+ and PO4^3- ions. KNO3 dissociates into K+ and NO3- ions.

Therefore, the ionic equation for the reaction is:

3Ag+ + 3NO3- + 3K+ + PO4^3- → Ag3PO4 + 3K+ + 3NO3-

Note that the K+ and NO3- ions appear on both sides of the equation and can be canceled out. The simplified ionic equation is:

Ag+ + PO4^3- → Ag3PO4

Molecular and Ionic Equations for the Reaction of Sodium Hydroxide with Phosphoric Acid:

The reaction between sodium hydroxide (NaOH) and phosphoric acid (H3PO4) can be represented by the following molecular equation:

NaOH + H3PO4 → NaH2PO4 + H2O

To write the ionic equation, we need to break down the reactants and products into their respective ions:

NaOH dissociates into Na+ and OH- ions. H3PO4 dissociates into H+ and H2PO4- ions. NaH2PO4 dissociates into Na+ and H2PO4- ions. H2O does not dissociate into ions.

Therefore, the ionic equation for the reaction is:

Na+ + OH- + H+ + H2PO4- → Na+ + H2PO4- + H2O

Note that the Na+ and H2PO4- ions appear on both sides of the equation and can be canceled out. The simplified ionic equation is:

OH- + H+ → H2O

Molecular and Ionic Equations for the Reaction of Phosphoric Acid with Potassium Hydroxide:

The reaction between phosphoric acid (H3PO4) and potassium hydroxide (KOH) can be represented by the following molecular equation:

H3PO4 + 3KOH → K3PO4 + 3H2O

To write the ionic equation, we need to break down the reactants and products into their respective ions:

H3PO4 dissociates into H+ and H2PO4- ions. 3KOH dissociates into 3K+ and 3OH- ions. K3PO4 dissociates into 3K+ and PO4^3- ions. 3H2O does not dissociate into ions.

Therefore, the ionic equation for the reaction is:

H+ + H2PO4- + 3K+ + 3OH- → 3K+ + PO4^3- + 3H2O

Note that the K+ ions appear on both sides of the equation and can be canceled out. The simplified ionic equation is:

H+ + H2PO4- + OH- → PO4^3- + H2O

I hope this helps! Let me know if you have any further questions.