Question

Решите задачу 2К+S=K2S Дано m(s)=6.4 Найти m(k)=?

Answer 1

Дано

2К+S=K2S

m(s)=6.4

Найти

m(k)=?

Решение

из уравнения видно, что в реакции задействовано

2К      +  S  =    K2S

2моль---1моль

соотношение 2:1

из условия видно, что

m(s)=6.4  г

M(s) = 32 г/моль

количество серы

n(s) = m/M = 6,4/32 = 0,2 моль

из соотношения получаем количество калия

n(k) = 0,2 * 2:1 = 0,4 моль

тогда масса калия

m(k) = M(k) * n(k) = 39 * 0,4 = 15,6 г

Ответ: m(k) = 15,6 г

Answer 2

The user's message is in Russian, so I will respond in Russian as well. The user is asking me to solve a problem involving a chemical reaction and mass calculations. I will use the information from the web search results to help me with the solution.

The problem is:

2K + S = K2S

Given: m(S) = 6.4 g

Find: m(K) = ?

To solve this problem, we need to use the law of conservation of mass, which states that the total mass of the reactants is equal to the total mass of the products in a chemical reaction. In other words, m(2K) + m(S) = m(K2S).

We also need to know the molar masses of the elements and compounds involved in the reaction. We can find them from the periodic table or online sources. They are:

M(K) = 39.1 g/mol M(S) = 32.1 g/mol M(K2S) = 110.3 g/mol

We can use these values to convert the given mass of sulfur into moles:

n(S) = m(S) / M(S) = 6.4 g / 32.1 g/mol = 0.199 mol

Then, we can use the stoichiometric coefficients of the balanced equation to find the moles of potassium:

n(2K) = 2 * n(S) = 2 * 0.199 mol = 0.398 mol

Finally, we can convert the moles of potassium into mass:

m(K) = n(K) * M(K) = 0.398 mol * 39.1 g/mol = 15.6 g

Therefore, the mass of potassium that reacts with sulfur is 15.6 g.

I hope this helps you understand how to solve this type of problem. If you need more practice, you can check out some online calculators or examples for solving quadratic equations involving chemical reactions.2K + S = K2S chemical reaction