Question

ОВР HNО3 + P => H3PO4 + NO2 + H2O

Answer 1

5H⁺N⁺⁵O₃⁻²+P⁰=H₃⁺P⁺⁵O₄⁻²+5N⁺⁴O₂⁻²+H⁺₂O⁻²
N⁺⁵---N⁺⁴ +1 е⁻ ВОССТАНАВЛИВАЕТСЯ, ОКИСЛИТЕЛЬ

P⁰   ---P⁺⁵  -5е⁻  окисляется, восстановитель 
до реакции вверху уравнения показываем переход электронов от  фосфора к азоту  и пишем -5е⁻ 

Answer 2

I can help you with your chemistry question. The equation you have given is an oxidation-reduction reaction, where phosphorus is oxidized and nitric acid is reduced. To balance the equation, you need to follow these steps:

1. Assign oxidation numbers to each element in the equation. For example, P has an oxidation number of 0, H has +1, N has +5, and O has -2. 2. Identify the atoms that are oxidized and reduced, and calculate the change in oxidation numbers. For example, P is oxidized from 0 to +5, and N is reduced from +5 to +4. 3. Write the half-reactions for oxidation and reduction, and balance the atoms and charges. For example, the oxidation half-reaction is P -> H3PO4 + 5e-, and the reduction half-reaction is HNO3 + e- -> NO2 + H2O. 4. Multiply the half-reactions by appropriate coefficients to make the total number of electrons equal on both sides. For example, multiply the oxidation half-reaction by 4 and the reduction half-reaction by 5. 5. Add the half-reactions together and cancel out any common terms. For example, the balanced equation is 4P + 20HNO3 -> 4H3PO4 + 20NO2 + 8H2O.

You can find more detailed explanations and examples of balancing oxidation-reduction equations on these websites: [Toppr](https://www.toppr.com/ask/question/balance-the-following-equationsp-hno3-rightarrow-no2-h2o-h3po4/), [Chegg](https://www.chegg.com/homework-help/questions-and-answers/exercise-16-instructor-oxidation-reduction-equations-balance-following-oxidation-reduction-q45228446).