Question

Na2(снизу)CO(снизу) + HNO3(снизу= ? KOH + H3(снизу)PO4(снизу)=? AlCl3(снизу) + KOH = ? Составить молекулярные, сокращённые ионные, полные ионные уравнения, помогите пожалуйста, не поняла!!!

Answer 1

Na2CO3 +2 HNO3 = 2NaNO3 + CO2 + H2O

2Na(+) + CO3(-2) + 2H(+) + 2NO3(-) = 2Na(+) + 2NO3(-) + CO2 + H2O

CO3(-2) + 2H(+) = CO2 + H2O

3KOH + H3PO4 = K3PO4 + 3H2O

3K(+) + 3OH(-) + 3H(+) + PO4(-3) = 3K(+) + PO4(-3) + 3H2O

3OH(-) + 3H(+) = 3H2O

AlCl3 + 3KOH = Al(OH)3 + 3KCl

Al(+3) + 3Cl(-) + 3K(+) + 3OH(-) = Al(OH)3 + 3K(+) + 3Cl(-)

Al(+3) + 3OH(-) = Al(OH)3

Answer 2

Balancing Chemical Equations

Balancing chemical equations involves ensuring that the same number of each type of atom is present on both sides of the equation. Let's break down the given chemical reactions step by step.

Na2CO3 + HNO3 = ?

The reaction between sodium carbonate (Na2CO3) and nitric acid (HNO3) can be represented as follows:

Molecular Equation: Na2CO3 + 2HNO3 → 2NaNO3 + H2O + CO2

Ionic Equation: 2Na+ + CO3^2- + 2H+ + 2NO3- → 2Na+ + 2NO3- + H2O + CO2

Net Ionic Equation: CO3^2- + 2H+ → H2O + CO2

KOH + H3PO4 = ?

The reaction between potassium hydroxide (KOH) and phosphoric acid (H3PO4) can be represented as follows:

Molecular Equation: 3KOH + H3PO4 → K3PO4 + 3H2O

Ionic Equation: 3K+ + 3OH- + H3PO4 → K3PO4 + 3H2O

Net Ionic Equation: H3PO4 + 3OH- → K3PO4 + 3H2O

AlCl3 + KOH = ?

The reaction between aluminum chloride (AlCl3) and potassium hydroxide (KOH) can be represented as follows:

Molecular Equation: AlCl3 + 3KOH → Al(OH)3 + 3KCl

Ionic Equation: Al^3+ + 3Cl- + 3K+ + 3OH- → Al(OH)3 + 3K+ + 3Cl-

Net Ionic Equation: Al^3+ + 3OH- → Al(OH)3

I hope this helps! Let me know if you have further questions or need additional assistance.