Question

Закончите уравнения химических реакций и расставьте коэффициенты K2 S+CuCI2 ->KCI+? Na2 O+H3 PO4 ->Na3 PO4 +? Fe S+HCI->?+?

Answer 1

K₂S + CuCI₂ = 2KCI + СuS↓
3Na₂O + 2H₃PO₄ = 2Na₃PO₄ + 3H₂O
FeS + 2HCI = FeCI₂ + H₂S↑

Answer 2

Balancing Chemical Equations

To balance the given chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance each equation step by step:

1. K2 + S + CuCl2 -> KCl + ?

To balance this equation, we need to ensure that the number of potassium (K), sulfur (S), copper (Cu), and chlorine (Cl) atoms is the same on both sides.

Let's start by balancing the potassium (K) atoms. There are two potassium atoms on the left side and one on the right side. To balance them, we can put a coefficient of 2 in front of KCl:

K2 + S + CuCl2 -> 2KCl + ?

Next, let's balance the sulfur (S) atoms. There is one sulfur atom on the left side and one on the right side, so sulfur is already balanced.

Now, let's balance the copper (Cu) atoms. There is one copper atom on the left side and none on the right side. To balance them, we can put a coefficient of 1 in front of CuCl2:

K2 + S + CuCl2 -> 2KCl + Cu

Finally, let's balance the chlorine (Cl) atoms. There are two chlorine atoms on the left side and one on the right side. To balance them, we can put a coefficient of 2 in front of CuCl2:

K2 + S + 2CuCl2 -> 2KCl + Cu

Therefore, the balanced equation is:

K2 + S + 2CuCl2 -> 2KCl + Cu

2. Na2O + H3PO4 -> Na3PO4 + ?

To balance this equation, we need to ensure that the number of sodium (Na), oxygen (O), hydrogen (H), and phosphorus (P) atoms is the same on both sides.

Let's start by balancing the sodium (Na) atoms. There are two sodium atoms on the left side and three on the right side. To balance them, we can put a coefficient of 2 in front of Na3PO4:

2Na2O + H3PO4 -> Na3PO4 + ?

Next, let's balance the oxygen (O) atoms. There are four oxygen atoms on the left side and four on the right side, so oxygen is already balanced.

Now, let's balance the hydrogen (H) atoms. There are three hydrogen atoms on the left side and none on the right side. To balance them, we can put a coefficient of 6 in front of H3PO4:

2Na2O + 6H3PO4 -> Na3PO4 + ?

Finally, let's balance the phosphorus (P) atoms. There is one phosphorus atom on the left side and one on the right side, so phosphorus is already balanced.

Therefore, the balanced equation is:

2Na2O + 6H3PO4 -> 3Na3PO4 + ?

3. Fe + S + HCl -> ?

To balance this equation, we need to ensure that the number of iron (Fe), sulfur (S), hydrogen (H), and chlorine (Cl) atoms is the same on both sides.

Let's start by balancing the iron (Fe) atoms. There is one iron atom on the left side and none on the right side. To balance them, we can put a coefficient of 1 in front of FeCl2:

Fe + S + HCl -> FeCl2 + ?

Next, let's balance the sulfur (S) atoms. There is one sulfur atom on the left side and one on the right side, so sulfur is already balanced.

Now, let's balance the hydrogen (H) atoms. There is one hydrogen atom on the left side and two on the right side. To balance them, we can put a coefficient of 2 in front of HCl:

Fe + S + 2HCl -> FeCl2 + ?

Finally, let's balance the chlorine (Cl) atoms. There are two chlorine atoms on the left side and two on the right side, so chlorine is already balanced.

Therefore, the balanced equation is:

Fe + S + 2HCl -> FeCl2 + ?

Please note that the question marks indicate that there may be additional products or reactants that are not specified in the given equations.