Question

Какое количество вещества составляют 32г Цинка?

Answer 1

N(Zn) =m/M=32/65=0,492

Answer 2

Amount of Zinc in 32g

Zinc has a molar mass of approximately 65.38 g/mol. To find the amount of substance in 32g of zinc, we can use the formula:

Amount of substance (in moles) = Mass / Molar mass

Plugging in the values: Amount of substance = 32g / 65.38 g/mol

Calculating this gives us: Amount of substance ≈ 0.49 moles of zinc

This means that 32g of zinc constitutes approximately 0.49 moles of the substance