Question

Над порошком оксида кальция массой 5,6 г пропускали углекислый газ. Объём вступившего в реакцию газа 3,36 л. Вычислите массу (г) образовавшегося карбоната кальция.

Answer 1

Вот так должно быть!!

Answer 2

Calculation of the Mass of Calcium Carbonate Formed

To calculate the mass of calcium carbonate formed, we need to use the stoichiometry of the reaction between calcium oxide (CaO) and carbon dioxide (CO2). The balanced equation for this reaction is:

CaO + CO2 → CaCO3

According to the given information, the mass of calcium oxide (CaO) is 5.6 g, and the volume of carbon dioxide (CO2) involved in the reaction is 3.36 L.

To calculate the mass of calcium carbonate (CaCO3) formed, we can use the following steps:

Step 1: Convert the volume of carbon dioxide (CO2) to moles using the ideal gas law. Step 2: Use the stoichiometry of the balanced equation to determine the moles of calcium carbonate (CaCO3) formed. Step 3: Convert the moles of calcium carbonate (CaCO3) to grams using the molar mass of calcium carbonate.

Let's calculate the mass of calcium carbonate (CaCO3) formed using these steps.

Step 1: Convert the Volume of Carbon Dioxide (CO2) to Moles

To convert the volume of carbon dioxide (CO2) to moles, we can use the ideal gas law equation:

PV = nRT

Where: P = pressure (in atm) V = volume (in L) n = number of moles R = ideal gas constant (0.0821 L·atm/(mol·K)) T = temperature (in Kelvin)

Since the temperature is not given, we'll assume it to be standard temperature (273.15 K).

Using the given volume of 3.36 L, we can calculate the number of moles of carbon dioxide (CO2):

n = PV / RT

Substituting the values into the equation:

n = (1 atm) * (3.36 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

Calculating the value of 'n' will give us the number of moles of carbon dioxide (CO2) involved in the reaction.

Step 2: Use the Stoichiometry to Determine Moles of Calcium Carbonate (CaCO3) Formed

According to the balanced equation, the stoichiometric ratio between calcium oxide (CaO) and calcium carbonate (CaCO3) is 1:1. This means that for every 1 mole of calcium oxide (CaO) reacted, 1 mole of calcium carbonate (CaCO3) is formed.

Since we have the number of moles of carbon dioxide (CO2) from Step 1, we can assume that the number of moles of calcium oxide (CaO) is also the same.

Step 3: Convert Moles of Calcium Carbonate (CaCO3) to Grams

To convert the moles of calcium carbonate (CaCO3) to grams, we need to use the molar mass of calcium carbonate. The molar mass of calcium carbonate (CaCO3) is the sum of the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms.

The atomic masses are as follows: - Calcium (Ca): 40.08 g/mol - Carbon (C): 12.01 g/mol - Oxygen (O): 16.00 g/mol

The molar mass of calcium carbonate (CaCO3) is calculated as: 40.08 g/mol + 12.01 g/mol + (16.00 g/mol * 3) = 100.09 g/mol

Now, we can calculate the mass of calcium carbonate (CaCO3) formed by multiplying the number of moles of calcium carbonate (CaCO3) by the molar mass of calcium carbonate (CaCO3).

Let's perform the calculations:

1. Calculate the number of moles of carbon dioxide (CO2): - n = (1 atm) * (3.36 L) / (0.0821 L·atm/(mol·K) * 273.15 K) - n ≈ 0.144 moles

2. Since the stoichiometric ratio between calcium oxide (CaO) and calcium carbonate (CaCO3) is 1:1, the number of moles of calcium carbonate (CaCO3) formed is also approximately 0.144 moles.

3. Calculate the mass of calcium carbonate (CaCO3) formed: - Mass = number of moles * molar mass - Mass = 0.144 moles * 100.09 g/mol - Mass ≈ 14.41 g

Therefore, the mass of calcium carbonate (CaCO3) formed is approximately 14.41 grams.

Please note that the calculations provided are approximate due to rounding of decimal places during intermediate steps.