Question

Помогите написать уравнение реакции хлорида меди два и железа в молекулярной и ионной форме

Answer 1

CuCl2 + Fe = FeCl2 + Cu (реакция обмена)
Cu + 2Cl + Fe = Fe + 2Cl + Cu
вроде как-то так)

Answer 2

Writing the Equation for the Reaction of Copper(II) Chloride and Iron

To write the equation for the reaction between copper(II) chloride and iron in both molecular and ionic forms, we can use the provided information from the search results.

Molecular Form: The molecular equation for the reaction between copper(II) chloride and iron is as follows: CuCl2 + Fe → FeCl2 + Cu

Ionic Form: The ionic equation for the reaction can be represented as: Cu^2+ + 2Cl^- + Fe → Fe^2+ + 2Cl^- + Cu

These equations represent the chemical reaction between copper(II) chloride and iron in both molecular and ionic forms, as per the provided search results