Question

Какая масса СО2 выделиться при сгорании 10 литров бутана

Answer 1

Сначала мы находим химическое количество бутана:
n=10/22.4= 0,45моль
и через пропорцию находим химическое количество СО2:(СО2 возьмем за х)
0,45/2=х/8
выражаем отсюда х:0,45*8 / 2 = 1,8моль
А потом по формуле m=n*M находим массу СО2: M(СО2) = 40 г/моль
m=1,8* 40= 72 грамма

Answer 2

Calculating CO2 Emission from Burning Butane

To calculate the amount of CO2 produced from burning 10 liters of butane, we can use the chemical equation for the combustion of butane and the molar volume of gases at standard temperature and pressure.

The balanced chemical equation for the combustion of butane is: 2C4H10 + 13O2 → 8CO2 + 10H2O

From the equation, we can see that 2 moles of butane produce 8 moles of CO2.

Calculation

1. Calculate the moles of butane in 10 liters using the ideal gas law: - Using the molar volume of gases at standard temperature and pressure (STP) of 22.4 liters/mol, we can calculate the moles of butane. - 10 liters of butane at STP is equal to 10/22.4 = 0.4464 moles of butane.

2. Calculate the moles of CO2 produced: - From the balanced chemical equation, 2 moles of butane produce 8 moles of CO2. - Therefore, 0.4464 moles of butane will produce (8/2) * 0.4464 = 1.7856 moles of CO2.

3. Convert moles of CO2 to grams: - The molar mass of CO2 is approximately 44.01 g/mol. - Therefore, the mass of CO2 produced from burning 10 liters of butane is 1.7856 * 44.01 = 78.57 grams.

So, the mass of CO2 produced from burning 10 liters of butane is approximately 78.57 grams.