Question

Рассчитайте объем водорода полученного при взаимодействии 14.4г цинка изизбытком раствора соляной кислоты

Answer 1

Zn + 2HCl___ZnCl2 + H2
65,4 гр____________1 моль
14,4 гр_____________х моль
х=14,4/65,4=0,2202 моль
1 моль газа_____22,4 литра
0,2202 моль газа_____У литров
У=0,2202*22,4= ... литров

Answer 2

Calculating the Volume of Hydrogen Gas Produced

To calculate the volume of hydrogen gas produced when 14.4g of zinc reacts with an excess of hydrochloric acid, we can use the ideal gas law equation. The balanced chemical equation for the reaction between zinc and hydrochloric acid is:

Zn + 2HCl → ZnCl2 + H2

First, we need to determine the moles of zinc involved in the reaction. Then, we can use the stoichiometry of the balanced chemical equation to find the moles of hydrogen gas produced. Finally, we can use the ideal gas law to calculate the volume of hydrogen gas at standard temperature and pressure (STP).

Step 1: Calculate the Moles of Zinc

The molar mass of zinc (Zn) is approximately 65.38 g/mol. We can use this to calculate the moles of zinc:

Moles of Zn = Mass of Zn / Molar mass of Zn

Moles of Zn = 14.4g / 65.38 g/mol

Step 2: Use Stoichiometry to Find Moles of Hydrogen Gas

From the balanced chemical equation, we can see that 1 mole of zinc produces 1 mole of hydrogen gas. Therefore, the moles of hydrogen gas produced will be equal to the moles of zinc.

Step 3: Calculate the Volume of Hydrogen Gas at STP

At standard temperature and pressure (STP), the conditions are 0°C (273.15 K) and 1 atmosphere (atm) pressure. The molar volume of an ideal gas at STP is 22.4 liters/mol.

Volume of H2 = Moles of H2 * Molar volume at STP

Now, let's calculate the volume of hydrogen gas produced using the given information.

Calculation:

Moles of Zn = 14.4g / 65.38 g/mol = 0.22 moles of Zn

Moles of H2 = 0.22 moles

Volume of H2 = 0.22 moles * 22.4 liters/mol = 4.928 liters

Therefore, the volume of hydrogen gas produced when 14.4g of zinc reacts with an excess of hydrochloric acid is approximately 4.928 liters at STP.