Question

Сколько граммов силиката натрия образуется при сплавлении 100 г. песка,содержащего 92% оксида кремния с избытком соды?

Answer 1

SiO2+Na2CO3=Na2SiO3+CO2

m(чист)(SiO2)=100*0.92=92(г)
 
ню (SiO2)=92/60=1.5 моль

ню (SiO2)=ню ( Na2SiO3 )=1ю5 моль

m(Na2SiO3)=1.5*122=183 г 

Answer 2

Calculating the Amount of Sodium Silicate Formed

To calculate the amount of sodium silicate formed when 100g of sand, containing 92% silicon dioxide, is melted with an excess of soda, we can use the chemical equation for the reaction between sand (silicon dioxide) and soda (sodium carbonate). The balanced chemical equation for the reaction is:

Na2CO3 + SiO2 → Na2SiO3 + CO2

From the equation, we can see that 1 mole of sodium carbonate reacts with 1 mole of silicon dioxide to produce 1 mole of sodium silicate. Now, let's calculate the amount of sodium silicate formed.

Calculation Steps

1. Calculate the moles of silicon dioxide in 100g of sand. 2. Use the mole ratio from the balanced chemical equation to find the moles of sodium silicate formed. 3. Convert the moles of sodium silicate to grams.

Step 1: Calculate the Moles of Silicon Dioxide in 100g of Sand

The molar mass of silicon dioxide (SiO2) is approximately 60.08 g/mol.

The moles of silicon dioxide in 100g of sand can be calculated using the formula: \[ \text{moles} = \frac{\text{mass}}{\text{molar mass}} \]

\[ \text{moles of SiO2} = \frac{100g \times 0.92}{60.08g/mol} \]

\[ \text{moles of SiO2} \approx 1.52 \]

Step 2: Use the Mole Ratio to Find the Moles of Sodium Silicate Formed

From the balanced chemical equation, the mole ratio of silicon dioxide to sodium silicate is 1:1.

So, the moles of sodium silicate formed will also be approximately 1.52.

Step 3: Convert the Moles of Sodium Silicate to Grams

The molar mass of sodium silicate (Na2SiO3) is approximately 122.06 g/mol.

The mass of sodium silicate formed can be calculated using the formula: \[ \text{mass} = \text{moles} \times \text{molar mass} \]

\[ \text{mass of Na2SiO3} = 1.52 \times 122.06g/mol \]

\[ \text{mass of Na2SiO3} \approx 185.61g \]

Therefore, approximately 185.61 grams of sodium silicate are formed when 100 grams of sand, containing 92% silicon dioxide, is melted with an excess of soda.

This calculation is based on the chemical reaction between silicon dioxide and sodium carbonate, as represented by the balanced chemical equation provided.