Question

CH3-COONa->CH3-COOH->CH3-COOC2H5OH->CH3-COOH

Answer 1

1. 2CH₃COONa + H₂SO₄ = 2CH₃COOH + Na₂SO₄
2. CH₃COOH + C₂H₅OH =(в прис. H₂SO₄; t⁰) CH₃COOCH₃CH₂ + H₂O
3. CH₃COOCH₃CH₂ + H₂O = CH₃COOH + C₂H₅OH

Answer 2

The chemical reactions you've provided appear to be a series of transformations involving the conversion of a sodium salt of acetic acid (CH3-COONa) into acetic acid (CH3-COOH), then into ethyl acetate (CH3-COOC2H5OH), and finally back into acetic acid (CH3-COOH). Let's break down each step:

1. CH3-COONa → CH3-COOH: This first step involves the conversion of the sodium salt of acetic acid (sodium acetate, CH3-COONa) into acetic acid (CH3-COOH) by the addition of a strong acid or by exchanging sodium ions with hydrogen ions. This reaction is typically carried out by treating sodium acetate with a strong mineral acid like hydrochloric acid (HCl) or sulfuric acid (H2SO4).

2. CH3-COOH → CH3-COOC2H5OH: In this step, acetic acid (CH3-COOH) reacts with ethanol (C2H5OH) to form ethyl acetate (CH3-COOC2H5OH). This is an esterification reaction, where the alcohol (ethanol) and the carboxylic acid (acetic acid) react to produce an ester (ethyl acetate) and water (H2O). The reaction typically requires a strong acid catalyst, such as sulfuric acid (H2SO4).

3. CH3-COOC2H5OH → CH3-COOH: In the final step, ethyl acetate (CH3-COOC2H5OH) can be hydrolyzed back into acetic acid (CH3-COOH) by the addition of water (H2O) and a strong acid or a base. Hydrolysis of esters typically requires the presence of an acid or base to catalyze the reaction. In this case, if you want to regenerate acetic acid, you can use a strong acid catalyst.

So, these reactions represent a series of chemical transformations involving acetic acid and its derivatives. Each step involves specific reagents and conditions to convert one compound into another as described.