Question

MgCo3+H3Po4=Mg3(Po4)2+H2Co3

Answer 1

3MgCO3 + 2H3PO4 = Mg3(PO4)2 + 3CO2 + 3H2O

3MgCO3 + 6H(+) + 2PO4(-3) = Mg3(PO4)2 + 3CO2 + 3H2O

Answer 2

The given chemical equation is not balanced. To balance it, we need to ensure that the same number of each type of atom is present on both sides of the equation. Let's balance the equation step by step:

MgCO3 + H3PO4 = Mg3(PO4)2 + H2CO3

Step 1: Balance the phosphate (PO4) ions: On the left side, we have one phosphate ion (H3PO4), and on the right side, we have two phosphate ions (Mg3(PO4)2). To balance this, we put a coefficient of 2 in front of H3PO4:

MgCO3 + 2H3PO4 = Mg3(PO4)2 + H2CO3

Step 2: Balance the magnesium (Mg) atoms: On the left side, we have one Mg atom in MgCO3, and on the right side, we have three Mg atoms in Mg3(PO4)2. To balance this, we put a coefficient of 3 in front of MgCO3:

3MgCO3 + 2H3PO4 = Mg3(PO4)2 + H2CO3

Step 3: Balance the carbon (C) atoms: On the left side, we have three C atoms in 3MgCO3, and on the right side, we have one C atom in H2CO3. To balance this, we put a coefficient of 3 in front of H2CO3:

3MgCO3 + 2H3PO4 = Mg3(PO4)2 + 3H2CO3

Now the equation is balanced with respect to the number of atoms of each element on both sides. The balanced equation is:

3MgCO3 + 2H3PO4 = Mg3(PO4)2 + 3H2CO3