Question

CH4 -> CH3Cl ->(над стрелочкой NaCH3Cl) ->C2H16 -> C2H4 -> C6H6

Answer 1

CH4 -> CH3Cl ->(над стрелочкой NaCH3Cl) ->C2H16 -> C2H4 -> C6H6

опечатка: не C2H16, а должно быть C2H6

CH₄ + Cl₂ --> CH₃Cl + HCl (hv)

CH₃Cl + CH₃Cl + 2Na --> C₂H₆ + 2NaCl

C₂H₆ ---> C₂H₄ + H₂ (Kt=Ni,t)

C₂H₄ --> C₂H₂ + H₂ (Kt=Ni,t), 3C₂H₂ --> C₆H₆

Answer 2

The chemical reactions you've written seem to be a bit unclear, possibly due to formatting issues. However, based on the given sequence, I'll attempt to interpret and explain the reactions step by step:

1. CH4 (Methane) → CH3Cl (Methyl chloride) In this reaction, methane (CH4) reacts with chlorine (Cl2) to form methyl chloride (CH3Cl).

2. CH3Cl (Methyl chloride) → (NaNH2) → C2H6 (Ethane) The given arrow "(NaNH2)" suggests the use of sodium amide (NaNH2), a strong base often used in organic reactions. It's likely that methyl chloride reacts with NaNH2 to form ethane (C2H6). The reaction would look like this: CH3Cl + NaNH2 → C2H6 + NaCl

3. C2H6 (Ethane) → C2H4 (Ethene) In this step, ethane (C2H6) undergoes a dehydrogenation reaction to form ethene (C2H4). C2H6 → C2H4 + H2

4. C2H4 (Ethene) → C6H6 (Benzene) This step involves the dimerization of ethene (C2H4) molecules to form benzene (C6H6). 3C2H4 → C6H6

It's important to note that the chemical reactions mentioned above are simplifications, and actual reactions may involve specific reaction conditions, catalysts, and stoichiometry. Additionally, the "(NaNH2)" part of the sequence might not be correct, as NaNH2 is more commonly used as a strong base rather than a reagent in this context. If you have a more specific and accurate representation of the reactions, please feel free to share it, and I'll be happy to help you further!