Question

Сумма коэффисентов а реакиции Хромит+O2+K2Co3.... А 16 В 23 С 30 Г 37

Answer 1

4Fe(CrO₂)₂ +7O₂+ 8K₂CO₃ = 8K₂CrO₄ + 2Fe₂O₃ + 8CO₂  

Сумма коэффициентов в реакции:

Г 37

Answer 2

To balance the chemical equation for the reaction of Chromite (Cr2O3) with Oxygen (O2) and Potassium Carbonate (K2CO3), we need to write the balanced equation first:

Cr2O3 + O2 + 2K2CO3 -> 2CrO3 + 2K2O + 3CO2

Now, we can identify the coefficients of the reactants and products:

Reactants: Cr2O3: coefficient = 1 O2: coefficient = 1 K2CO3: coefficient = 2

Products: CrO3: coefficient = 2 K2O: coefficient = 2 CO2: coefficient = 3

Now, let's calculate the sum of the coefficients for the reactants (a, b, and c) and products (d, e, and f):

a (Cr2O3) + b (O2) + c (K2CO3) = 1 + 1 + 2 = 4 d (CrO3) + e (K2O) + f (CO2) = 2 + 2 + 3 = 7

The sum of coefficients for the reactants (a + b + c) is 4, and the sum of coefficients for the products (d + e + f) is 7. Adding them together:

4 + 7 = 11

So, the sum of the coefficients on both sides of the balanced chemical equation is 11.