Question

CH3-CH2Br--->CH3=CH2 CH3-CH2Br--->CH3-CH2-CH2-CH3 CH3-CH2-CH2-CH3--->CH3-CH=CH-CH3

Answer 1

CH₃-CH₂Br (KOH (спирт)) ->  СH₂=CH₂ + HBr (ты скорее всего ошибся, у углеродов в орг. соединениях валентность 4)

2CH₃-CH₂-Br + 2Na -> СH₃-CH₂-CH₂-CH₃ + 2NaBr

СH₃-CH₂-CH₂-CH₃ (t°, Ni) -> СH₃-CH=CH-CH₃ + H₂↑

Answer 2

The three reactions you've provided are examples of organic chemical reactions involving alkyl halides. Let's analyze each of them:

1. CH3-CH2Br -> CH3=CH2 This reaction is an example of an elimination reaction, specifically a dehydrohalogenation. In this reaction, the alkyl halide CH3-CH2Br (1-bromopropane) undergoes elimination of a hydrogen atom and a bromine atom (hydrogen bromide, HBr) to form propene (CH3=CH2).

2. CH3-CH2Br -> CH3-CH2-CH2-CH3 This reaction is an example of a substitution reaction, specifically a nucleophilic substitution. In this reaction, the alkyl halide CH3-CH2Br (1-bromopropane) undergoes substitution of the bromine atom with a nucleophilic species (e.g., hydroxide ion OH-) to form butane (CH3-CH2-CH2-CH3).

3. CH3-CH2-CH2-CH3 -> CH3-CH=CH-CH3 This reaction is an example of an elimination reaction, specifically a dehydrogenation. In this reaction, the alkane butane (CH3-CH2-CH2-CH3) undergoes elimination of two hydrogen atoms to form butene (CH3-CH=CH-CH3).

It's important to note that organic reactions can be influenced by reaction conditions, reagents, and catalysts. The specific details of each reaction would depend on the exact conditions under which they are carried out.