Question

Пропин+О2 Пропен+О2 Метан+Cl2

Answer 1

Ответ:

с кислородом в обеих реакциях получается углекислый газ и вода. Метан и хлор будет хлорметан и хлороводород

Answer 2

The expressions you provided appear to be chemical reactions involving different gases and elements. Let's break down each reaction:

1. Пропин + О2 (Propyne + Oxygen): This is the combustion reaction of propyne (C3H4) with oxygen (O2). The reaction equation is as follows: C3H4 + 5O2 → 3CO2 + 2H2O

2. Пропен + О2 (Propene + Oxygen): This is also a combustion reaction, but this time involving propene (C3H6) and oxygen (O2). The reaction equation is as follows: C3H6 + 9/2 O2 → 3CO2 + 3H2O

3. Метан + Cl2 (Methane + Chlorine): This is a reaction between methane (CH4) and chlorine gas (Cl2). The reaction between methane and chlorine is a radical substitution reaction. In the presence of UV light or heat, the following reaction occurs: CH4 + Cl2 → CH3Cl + HCl

Please note that chemical reactions should be conducted with proper safety precautions, and some of the reactions mentioned above may be potentially hazardous. Always ensure you have the necessary knowledge, training, and equipment before attempting any chemical reactions.