Question

СuS04 → Сu (ОН)2 → СuО→ Сu

Answer 1

Ответ:

1) CuSO4 + 2NaOH ---> Na2SO4 + Cu(OH)2 (стрелочка вниз)

2) Cu(OH)2 --(t)--> CuO + H2O

3) CuO + H2 ---> Cu + H2O

Answer 2

Ответ:

) 2Cu+O2=2CuO

2)CuO+2HCl=CuCl2+H2O

3)CuCl2+2KOH=Cu(OH)2+2KCl

4)Cu(OH)2=CuO+H2O (при нагревании)

5)CuO+H2SO4=CuSO4+H2O

(то?)

Объяснение:

Answer 3

The chemical equation you provided seems to represent the reaction pathway for the decomposition of copper(II) sulfate (CuSO4) into copper metal (Cu). Let's break down the steps of the reaction:

1. CuSO4 (copper(II) sulfate) → Cu(OH)2 (copper hydroxide) This step involves the reaction of copper(II) sulfate with a base (e.g., sodium hydroxide) to form copper(II) hydroxide, which is a blue precipitate.

2. Cu(OH)2 (copper hydroxide) → CuO (copper oxide) In this step, copper(II) hydroxide loses a water molecule and converts to copper(II) oxide, which is a black solid.

3. CuO (copper oxide) → Cu (copper metal) Finally, copper(II) oxide undergoes reduction, where it loses oxygen and forms copper metal.

The overall equation can be summarized as: CuSO4 → Cu(OH)2 → CuO → Cu

It's worth noting that this reaction pathway typically involves the addition of a base to the copper(II) sulfate solution, which then leads to the formation of the copper(II) hydroxide precipitate. The copper(II) hydroxide is then heated to produce copper(II) oxide, which is further reduced to form copper metal. The process is often used in laboratory settings to obtain pure copper metal from copper(II) sulfate solutions.