Question

Сумма коэффициентов в ряду превращений P → P2O5 → H3PO4 равна(коэффициент 1 учитывать) * 16 17 5 0

Answer 1

$P=>P_2O_5=>H_3PO_4\\4P+5O_2=>2P_2O_5$

$>2H_3PO_4$

Сумма коэффициентов равна

4+5+2+3+1+2=17

Answer 2

To find the sum of the coefficients in the chemical equation P → P2O5 → H3PO4, we need to balance the equation first. The balanced equation is as follows:

1P → 2P2O5 → 2H3PO4

Now, let's list the coefficients of each compound in the equation:

P: 1 P2O5: 2 H3PO4: 2

The sum of the coefficients is:

1 + 2 + 2 = 5

So, the sum of the coefficients in the given chemical equation is 5.