Question

CH4-CH3Br-C2H6-C2H4-C2H4-Br

Answer 1

Ответ:CH4 -> CH3Br -> C2H6 -> C2H4 -> C2H2 -> C6H6

1) CH4 + Br2 -> CH3Br + HBr

2) 2CH3Br + 2Na -> CH3-CH3 + 2NaBr

3) CH3-CH3 ->(t)-> CH2=CH2 + H2

4) CH2=CH2 ->(t)-> CH(тройная связь, три палочки)CH + H2

5) 3CH(три палочки)CH ->(Cакт,t=500C)-> C6H6 - тримеризация ацетилена (реакция Зелинского)

Объяснение:

Answer 2

The given sequence of chemical compounds appears to be a combination of hydrocarbons and halogen-substituted hydrocarbons. Let's break down each compound in the sequence:

1. CH4: Methane, a simple hydrocarbon with one carbon atom and four hydrogen atoms.
2. CH3Br: Methyl bromide, a halogen-substituted hydrocarbon with one carbon atom, three hydrogen atoms, and one bromine atom.
3. C2H6: Ethane, a hydrocarbon with two carbon atoms and six hydrogen atoms.
4. C2H4: Ethene (also known as ethylene), a hydrocarbon with two carbon atoms and four hydrogen atoms. It's an unsaturated molecule with a double bond between the carbon atoms.
5. C2H4: Another molecule of ethene (ethylene).
6. Br: Bromine, a halogen element.

The sequence can be summarized as follows:

Methane (CH4) - Methyl Bromide (CH3Br) - Ethane (C2H6) - Ethene (C2H4) - Ethene (C2H4) - Bromine (Br)

It appears to be a combination of different hydrocarbons and a halogen element (bromine) within the sequence. If you have specific questions about the sequence or its significance, feel free to ask!