Question

M (CO2)= 1,4г V (CO2)=?

Answer 1

Ответ:

Объяснение:

Дано:

m(CO2)=1,4 г

V(CO2)-?

Решение:

n=m/M , M(CO2)=12+2×16=44г/моль

n(CO2)=1,4г / 44г/моль = 0,03 моль

V=n×Vm , Vm=22,4л/моль

V(CO2)=0,03моль × 22,4л/моль = 0,672 л

Ответ: V(CO2)=0,672 л

Answer 2

To calculate the volume (V) of carbon dioxide (CO2) gas when you know the mass (M) of CO2, you'll need to use the ideal gas law:

PV = nRT

Where: P = pressure (in Pascals, Pa) V = volume (in cubic meters, m^3) n = number of moles R = ideal gas constant (8.314 J/(mol·K)) T = temperature (in Kelvin, K)

First, you need to find the number of moles (n) of CO2 using the given mass (M) and the molar mass of CO2, which is approximately 44.01 g/mol.

n = M / molar mass n = 1.4 g / 44.01 g/mol ≈ 0.03182 moles

Now, you need to know the temperature (T) and pressure (P) of the CO2 gas to calculate the volume (V). If you have that information, you can rearrange the ideal gas law to solve for V:

V = (nRT) / P

Plug in the values:

V = (0.03182 moles * 8.314 J/(mol·K) * T) / P

Make sure the temperature is in Kelvin and pressure is in Pascals for this equation to work. Once you have the values for T and P, you can calculate the volume (V) in cubic meters (m^3).

If you have the temperature and pressure, please provide those values so I can help you calculate the volume.