Question

Co2+nacl=?co2+caoh=?​

Answer 1

Объяснение:

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1)Na2CO3+Cl2

2)CaCO3+H2O

Answer 2

It seems like you want to know the products of chemical reactions involving carbon dioxide (CO2) with sodium chloride (NaCl) and calcium hydroxide (Ca(OH)2). Let's look at each reaction separately:

1. Reaction between CO2 and NaCl: CO2 (carbon dioxide) is a non-metallic gas, and NaCl (sodium chloride) is an ionic compound. When CO2 is bubbled through a solution of NaCl, it does not undergo a chemical reaction. Instead, it dissolves in water to form carbonic acid (H2CO3) but doesn't result in any solid product. The equation for this dissolution is as follows: CO2 + H2O → H2CO3

2. Reaction between CO2 and Ca(OH)2: CO2 can react with calcium hydroxide (Ca(OH)2) to form calcium carbonate (CaCO3), which is a white solid precipitate. This reaction is often used in carbon capture processes. The balanced chemical equation for this reaction is: CO2 + Ca(OH)2 → CaCO3 + H2O

So, in the second reaction, the products are calcium carbonate (CaCO3) and water (H2O).

Answer 3

The chemical equations you provided are a bit unclear, but I will try to interpret what you're asking for.

1. Co2 + NaCl:

This equation doesn't represent a chemical reaction. CO2 (carbon dioxide) and NaCl (sodium chloride) are both compounds, and they do not react with each other in a simple chemical reaction. Carbon dioxide is a non-metallic gas, and sodium chloride is a salt. These two substances do not combine to produce a chemical reaction in the way that elements or certain compounds do.

2. CO2 + Ca(OH)2:

This equation represents the reaction between carbon dioxide (CO2) and calcium hydroxide (Ca(OH)2). When CO2 reacts with Ca(OH)2, it forms calcium carbonate (CaCO3) and water (H2O) as products. The balanced chemical equation for this reaction is:

CO2 + Ca(OH)2 → CaCO3 + H2O

In this reaction, carbon dioxide reacts with calcium hydroxide to produce calcium carbonate, which is a white solid, and water.

If you have any more specific questions or need further clarification, please feel free to ask.