Question

V=20 T=22 P=500 KPA m(co2) =?​

Answer 1

Ответ: m=MPV/RT= 44•500•20/8.314•20= 2405 г

Объяснение:

Answer 2

To calculate the mass of carbon dioxide (CO2), you can use the ideal gas law, which relates pressure (P), volume (V), temperature (T), and the number of moles of a gas (n). The ideal gas law is expressed as:

PV = nRT

Where: P = Pressure (in pascals) V = Volume (in cubic meters) n = Number of moles of gas R = Universal gas constant (8.314 J/(mol·K)) T = Temperature (in kelvin)

First, you need to convert the given pressure and temperature to SI units (pascals and kelvin):

P = 500 kPa = 500,000 Pa T = 22°C = 22 + 273.15 K = 295.15 K

Now, you can use the ideal gas law to calculate the number of moles of CO2 (n):

PV = nRT

n = (PV) / (RT)

n = (500,000 Pa * 20 m³) / (8.314 J/(mol·K) * 295.15 K)

n ≈ 340.07 moles

So, there are approximately 340.07 moles of carbon dioxide (CO2) in the given conditions.

Now, if you want to calculate the mass of CO2 (m), you can use the molar mass of CO2, which is approximately 44.01 g/mol:

m = n * M

m = 340.07 moles * 44.01 g/mol ≈ 14,971.34 grams

Therefore, the mass of carbon dioxide (CO2) is approximately 14,971.34 grams, or 14.97 kilograms (since 1 kilogram is 1000 grams).