Question

К 1 л 20%-го раствора гидроксида натрия (p = 1,22 г/мл) прибавили 10 л воды. Определите процентную концентрацию полученного раствора.

Answer 1

Ответ:

1) масса гидроксида натрия = 1,22 / 5 * 1000= 244г

2) общая масса = 10000 + 1220 = 11220г - масса 10л воды + масса раствора (1л)

3) процентное содержание = 244 / (11220 / 100) = 2,1747...% - масса гидроксида / (один процент от общей массы)

Answer 2

Calculation of the Concentration of Sodium Hydroxide Solution

To determine the percentage concentration of the resulting solution, we need to consider the initial concentration of the sodium hydroxide solution and the volume of water added.

Given: - Initial concentration of sodium hydroxide solution: 1.22 g/mL (20% solution) - Volume of water added: 10 L

To calculate the concentration of the resulting solution, we can use the formula:

Concentration = (mass of solute / volume of solution) * 100

Let's calculate the concentration step by step:

1. Convert the volume of water added from liters to milliliters: - 10 L * 1000 mL/L = 10,000 mL

2. Calculate the mass of the solute (sodium hydroxide) in the initial solution: - Mass of solute = Initial concentration * Volume of solution - Mass of solute = 1.22 g/mL * 10,000 mL = 12,200 g

3. Calculate the volume of the resulting solution: - Volume of resulting solution = Volume of initial solution + Volume of water added - Volume of resulting solution = 10,000 mL + 10,000 mL = 20,000 mL

4. Calculate the concentration of the resulting solution: - Concentration = (Mass of solute / Volume of resulting solution) * 100 - Concentration = (12,200 g / 20,000 mL) * 100

Now, let's calculate the concentration using the given values:

Concentration = (12,200 g / 20,000 mL) * 100

Concentration = 61%

Therefore, the percentage concentration of the resulting solution is 61%.