Question

СРОЧНО, ДАЮ 90 БАЛЛОВ Дать характеристику реакциям и уравнять ихCaO+H2O=Ca(OH)2Fe2O3+HCI=FeCI3+H2OCuOH=Cu2O+H2ONaCI+AgNO3=AgCI+NaNO3СРОЧНО, ПОЖАЛУЙСТА​

Answer 1

Ответ:

CaO+H2O=Ca(OH)2 реакция соединения, необратимая, гетерогенная, экзотермическая. Не окислительно-восстановительная

Fe2O3+6HCI=2FeCI3+3H2O обмена, необратимая, гетерогенная, не окислительно,-восстановительная, экзотермическая

2CuOH=Cu2O+H2O реакция разложения, необратимая, гетерогенная, окислительно-восстановительная, эндотермическая

NaCI+AgNO3=AgCI+NaNO3 обмена, необратимая, гетерогенная, не окислительно-восстановительная, экзотермическая

Объяснение:

Answer 2

Chemical Reactions and Equations

Let's analyze and balance the given chemical reactions:

1. CaO + H2O = Ca(OH)2

This is a reaction between calcium oxide (CaO) and water (H2O) to form calcium hydroxide (Ca(OH)2).

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation is:

CaO + H2O = Ca(OH)2 [[1]]

2. Fe2O3 + HCl = FeCl3 + H2O

This is a reaction between iron(III) oxide (Fe2O3) and hydrochloric acid (HCl) to form iron(III) chloride (FeCl3) and water (H2O).

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation is:

Fe2O3 + 6HCl = 2FeCl3 + 3H2O [[2]]

3. CuOH = Cu2O + H2O

This is a reaction between copper(II) hydroxide (CuOH) to form copper(I) oxide (Cu2O) and water (H2O).

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation is:

2CuOH = Cu2O + H2O [[3]]

4. NaCl + AgNO3 = AgCl + NaNO3

This is a reaction between sodium chloride (NaCl) and silver nitrate (AgNO3) to form silver chloride (AgCl) and sodium nitrate (NaNO3).

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

The balanced equation is:

NaCl + AgNO3 = AgCl + NaNO3 [[4]]

I hope this helps! Let me know if you have any further questions.