Question

Помогите пожалуйста, дам 100 баллов!! На нейтралізацію суміші двох насичених одноосновних кислот масою 35 г витрачено розчин калiй гiдроксиду масою 200 мл iз концентрацією 3,5 моль/л. Обчисліть масу кожного компонента у складі суміші, якщо відомо, що молярна маса однієї кислоти має однакове значення з молярною масою нітроген (IV) оксиду, а молярна маса другої кислоти вдвічі більша, ніж молярна маса етану.​

Answer 1

Объяснение:

${ - 6.056}^{?}$

Answer 2

To calculate the mass of each component in the mixture, we need to use the concept of stoichiometry. Given that the molar mass of one acid is the same as the molar mass of nitrogen (IV) oxide and the molar mass of the other acid is twice the molar mass of ethane, we can proceed with the following steps:

1. Determine the number of moles of potassium hydroxide (KOH) used: - Mass of KOH = 200 g - Concentration of KOH = 3.5 mol/L - Volume of KOH solution = 200 mL = 0.2 L - Number of moles of KOH = concentration × volume = 3.5 mol/L × 0.2 L = 0.7 mol

2. Since KOH reacts with the mixture of acids in a 1:1 ratio, the number of moles of the mixture of acids is also 0.7 mol.

3. Let's assume the molar mass of nitrogen (IV) oxide is M grams/mol. Therefore, the molar mass of one acid is also M grams/mol, and the molar mass of the other acid is 2M grams/mol.

4. We can set up the following equation based on the given information: M × x + 2M × (0.7 - x) = 35 g where x is the number of moles of the first acid.

5. Solving the equation, we find: M × x + 1.4M - 2M × x = 35 g -0.6M × x = 35 g - 1.4M x = (35 g - 1.4M) / (-0.6M)

6. Now, we can calculate the mass of each component in the mixture: - Mass of the first acid = M × x - Mass of the second acid = 2M × (0.7 - x)

Please note that we don't have the exact value of M, the molar mass of nitrogen (IV) oxide, or the molar mass of ethane. Therefore, we cannot provide the specific values for the masses of each component in the mixture. However, you can use the given equation and substitute the values of M and 2M to calculate the masses once you have those values.

I hope this helps! Let me know if you have any further questions.