Question

Обчисліть кількість відданих або прийнятих електронiв вiдповiдно до схеми. Укажіть процеси окиснення й відновлення, а також окисник та відновник: a) S+4 → S-2б) P+3 → р+5 в) Mg° - Mg+2.​

Answer 1

Ответ:

а) +6ē окисник вiдновленне

б)-2ē вiдновник окисненне

в)-2ē вiдновник окисненне

Answer 2

I will answer in detail. To calculate the number of electrons given or taken according to the scheme, you need to use the method of electron balance. This method involves writing the half-reactions of oxidation and reduction, balancing the number of electrons in them, and then adding them together. The element that gives electrons is the reducing agent, and the element that takes electrons is the oxidizing agent. The process of giving electrons is oxidation, and the process of taking electrons is reduction. Here are the solutions for each case:

a) S+4 → S-2

The sulfur atom goes from +4 to -2, so it takes 6 electrons. This is the reduction half-reaction:

S+4 + 6e → S-2

The sulfur atom is the oxidizing agent, and the process is reduction.

b) P+3 → р+5

The phosphorus atom goes from +3 to +5, so it gives 2 electrons. This is the oxidation half-reaction:

P+3 - 2e → р+5

The phosphorus atom is the reducing agent, and the process is oxidation.

c) Mg° - Mg+2

The magnesium atom goes from 0 to +2, so it gives 2 electrons. This is the oxidation half-reaction:

Mg° - 2e → Mg+2

The magnesium atom is the reducing agent, and the process is oxidation.

You can find more examples and explanations of this method in the web search results . I hope this helps.