Question

Какой объём водорода выделится при взаимодействии 20 г железа с разбавленной соляной кислотой!! Срочно!! Отдаю всё баллы ​

Answer 1

Ответ:

Fe+2H2O=FeCi2*4H2O+H2Mr(Fe)=56 (округленно)

Моль Fe=20:56=5/14

Моль Fe относится к Моль H2 как 1/1 , по условию реакции.

Таким образом Моль H2=5/14

5/14*22.4=8 л газа (H2)

Ответ 8 литров.

Объяснение:-----

Answer 2

Volume of Hydrogen Gas Produced from the Reaction

When 20 grams of iron reacts with dilute hydrochloric acid, the volume of hydrogen gas produced can be calculated using the stoichiometry of the reaction and the ideal gas law.

The balanced chemical equation for the reaction between iron and hydrochloric acid is:

Fe + 2HCl → FeCl2 + H2

From the balanced equation, it is clear that 1 mole of iron reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.

The molar mass of iron (Fe) is approximately 55.85 g/mol, and the molar mass of hydrogen (H2) is approximately 2.02 g/mol.

Using this information, we can calculate the number of moles of iron and the corresponding volume of hydrogen gas produced.

First, we need to convert the mass of iron to moles: - Number of moles of iron = Mass of iron / Molar mass of iron - Number of moles of iron = 20 g / 55.85 g/mol

Now, we can use the stoichiometry of the reaction to find the moles of hydrogen gas produced: - Number of moles of hydrogen gas = Number of moles of iron * (1 mole of H2 / 1 mole of Fe)

Finally, we can use the ideal gas law to calculate the volume of hydrogen gas at standard temperature and pressure (STP), which is 0°C and 1 atmosphere pressure: - Volume of hydrogen gas (at STP) = Number of moles of hydrogen gas * 22.4 L/mol

Let's calculate the volume of hydrogen gas produced using these calculations.

The molar mass of iron and the stoichiometry of the reaction can be verified from the search results.