Question

1.Обчисліть число атомів Оксигену в кисні об'ємом 67,2 л (н.у.).Срочно ​

Answer 1

Ответ:

Число атомов 3,612*10^24

Объяснение:

Молекула кислорода двуатомна

N(O2)=(67.2/22.4)*2*6.02*10^23=3,612*10^24

Answer 2

Calculating the Number of Oxygen Atoms in a Given Volume of Oxygen Gas

To calculate the number of oxygen atoms in a given volume of oxygen gas, we can use the ideal gas law equation, which relates the number of moles of a gas to its volume, pressure, and temperature. The ideal gas law equation is given by:

PV = nRT

Where: - P = pressure - V = volume - n = number of moles - R = ideal gas constant - T = temperature

Given: - Volume of oxygen gas (V) = 67.2 L - Standard temperature and pressure (STP) conditions: 0 °C (273 K) and 1 atm - Molar volume of a gas at STP = 22.4 L/mol

We can use the molar volume of a gas at STP to calculate the number of moles of oxygen gas present in the given volume.

Calculation:

Using the molar volume of a gas at STP: Number of moles (n) = Volume (V) / Molar volume at STP

Number of moles (n) = 67.2 L / 22.4 L/mol Number of moles (n) ≈ 3 moles

Now, to calculate the number of oxygen atoms, we can use Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, or formula units).

Calculation:

Number of oxygen atoms = Number of moles x Avogadro's number

Number of oxygen atoms = 3 moles x 6.022 x 10^23 atoms/mole Number of oxygen atoms ≈ 1.807 x 10^24 atoms

Therefore, the number of oxygen atoms in a volume of 67.2 L of oxygen gas at standard conditions is approximately 1.807 x 10^24 atoms.