Question

Вычислите массу оксида натрия образовавшегося при взаимодействии натрия с 1,6г кислорода

Answer 1

Ответ:

3.9 смотри решение на фото

Answer 2

Calculating the Mass of Sodium Oxide

To calculate the mass of sodium oxide formed from the reaction of sodium with 1.6g of oxygen, we can use the stoichiometry of the reaction between sodium and oxygen to determine the mass of sodium oxide produced.

The balanced chemical equation for the reaction between sodium and oxygen is:

4Na + O2 → 2Na2O

From the balanced equation, we can see that 4 moles of sodium react with 1 mole of oxygen to produce 2 moles of sodium oxide.

Given that the mass of oxygen is 1.6g, we can calculate the mass of sodium oxide formed using the molar masses of the elements involved.

The molar mass of sodium (Na) is approximately 22.99 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol.

Using this information, we can calculate the mass of sodium oxide formed.

Calculation

First, we need to find the number of moles of oxygen: 1.6g / 16.00 g/mol = 0.1 moles of oxygen

According to the balanced chemical equation, 4 moles of sodium react with 1 mole of oxygen to produce 2 moles of sodium oxide.

So, the number of moles of sodium oxide produced is: (0.1 moles of O2 * 2 moles of Na2O) / 1 mole of O2 = 0.2 moles of Na2O

Finally, we can calculate the mass of sodium oxide formed: 0.2 moles * 61.98 g/mol = 12.396g of sodium oxide

Therefore, the mass of sodium oxide formed when 1.6g of oxygen reacts with sodium is approximately 12.396g.