Question

2. Обчисліть, який об’єм кисню потрібний для спалювання 1 л етану. Який об’єм вуглекислого газу при цьому утвориться

Answer 1

0,045. х

C2H6+7O-->2CO2+3H2O

1. 7

0,045. х

C2H6+7O-->2CO2+3H2O

1 2

Объяснение:

n(C2H6)=V(C2H6)Vm=1:22,4=0,045моль(недостаток)

x(O)=0,045×7:1=0,315моль(избыток)

V(O)=n×Vm=0,315×22,4=7,056литров

х(CO2)=0,045×2:1=0,09моль

V(CO2)=n×Vm=0,09×22,4=2,016

Ответ: объем СО2-2,016литров; объем кислорода (O)-7,056литров

Answer 2

Calculating Oxygen Volume for Burning 1 Liter of Ethanol

To calculate the volume of oxygen needed for the combustion of 1 liter of ethanol, we can use the balanced chemical equation for the combustion of ethanol:

C2H5OH + 3O2 → 2CO2 + 3H2O

From the balanced equation, we can see that 1 mole of ethanol reacts with 3 moles of oxygen to produce 2 moles of carbon dioxide and 3 moles of water.

Using the molar volume of gases at standard temperature and pressure (STP), which is 22.4 liters per mole, we can calculate the volume of oxygen required and the volume of carbon dioxide produced.

The molar volume of gases at STP is 22.4 liters per mole.

The molar mass of ethanol (C2H5OH) is approximately 46.07 g/mol.

The molar mass of oxygen (O2) is approximately 32 g/mol.

Calculations

1. Moles of Ethanol: - 1 liter of ethanol at STP contains approximately 0.789 moles of ethanol. - This is calculated using the molar volume of gases at STP (22.4 liters/mole) and the molar mass of ethanol (46.07 g/mole).

2. Moles of Oxygen Needed: - According to the balanced chemical equation, 1 mole of ethanol requires 3 moles of oxygen. - Therefore, 1 liter of ethanol requires approximately 2.367 moles of oxygen. - This is calculated by multiplying the moles of ethanol by the stoichiometric coefficient of oxygen in the balanced equation.

3. Volume of Oxygen Needed: - The volume of 2.367 moles of oxygen at STP is approximately 53.1 liters. - This is calculated using the molar volume of gases at STP (22.4 liters/mole).

4. Volume of Carbon Dioxide Produced: - According to the balanced chemical equation, 1 mole of ethanol produces 2 moles of carbon dioxide. - Therefore, the combustion of 1 liter of ethanol produces approximately 1.578 moles of carbon dioxide. - The volume of 1.578 moles of carbon dioxide at STP is approximately 35.4 liters.

Conclusion

- Volume of Oxygen Needed for Burning 1 Liter of Ethanol: Approximately 53.1 liters. - Volume of Carbon Dioxide Produced: Approximately 35.4 liters.

These calculations are based on the stoichiometry of the balanced chemical equation for the combustion of ethanol and the molar volume of gases at STP.