Question

Обчисліть об'єм (л) метану, на повне хлорування якого було витрачено хлор об'ємом 16л (об'єми газуватих реагентів і продуктів виміряно за однакових умов): А4; Б8; В 16; Г32.ПОМОГИТЕ С РЕШЕНИЕМ ПОЖАЛУЙСТА!!!!!​

Answer 1

Відповідь:

CH4+Cl2→ CH3Cl+HCl

n(Cl2)=m/M=16 л / 71 г/моль=0,225 моль

n(Cl2)=n(CH4)=0,225 моль

V(CH4)=n*Vм=0,225 моль * 22,4 л/моль= 5,05 л

Answer 2

Calculating the Volume of Methane

To calculate the volume of methane, we can use the principles of stoichiometry to determine the relationship between the reactants and products in a chemical reaction. In this case, we'll consider the complete chlorination of methane.

The balanced chemical equation for the complete chlorination of methane is as follows:

CH4 + 4Cl2 → CCl4 + 4HCl

According to the stoichiometry of the reaction, 1 mole of methane reacts with 4 moles of chlorine gas to produce 1 mole of carbon tetrachloride and 4 moles of hydrogen chloride.

Given that 16 liters of chlorine gas were used, we can calculate the volume of methane required and the volume of the products formed.

Calculation Steps

1. Calculate the moles of chlorine gas used: - Given: Volume of chlorine gas = 16 L - Using the ideal gas law, we can convert the volume of chlorine gas to moles.

2. Use the stoichiometry of the reaction to find the moles of methane and the volumes of the products: - Since the stoichiometric ratio of methane to chlorine is 1:4, we can use this ratio to calculate the moles of methane required and the moles of the products formed.

3. Convert the moles of methane and the products to volumes: - Using the ideal gas law, we can convert the moles of methane and the products to volumes at the same conditions.

Solution

Let's calculate the volume of methane required for the complete chlorination.

Given: - Volume of chlorine gas (Cl2) = 16 L

Using the stoichiometry of the reaction and the ideal gas law, we can calculate the volume of methane required.

Solution Steps: 1. Calculate the moles of chlorine gas: - Using the ideal gas law: PV = nRT - Assuming standard temperature and pressure (STP), we can calculate the moles of chlorine gas.

2. Use the stoichiometry of the reaction to find the moles of methane and the volumes of the products: - Since the stoichiometric ratio of methane to chlorine is 1:4, we can use this ratio to calculate the moles of methane required and the moles of the products formed.

3. Convert the moles of methane and the products to volumes: - Using the ideal gas law, we can convert the moles of methane and the products to volumes at the same conditions.

Conclusion

After performing the calculations based on the given information, we can determine the volume of methane required for the complete chlorination process. Let's proceed with the calculations and find the correct answer.