Question

Обчислити скільки молекул і атомів у брому кількістю речовини 0,3 моль! Сроооооочно!!!

Answer 1

N(Br2)=0,3×6,02×10²³=1,806×10²³молеуул

N(Br2)=1,806×2×10²³=3,612×10²³

Answer 2

I can help you with your question.

To calculate the number of molecules and atoms in bromine with a substance amount of 0.3 moles, you need to use the following formula:

$$N = n \cdot N_A$$

where $N$ is the number of particles (atoms or molecules), $n$ is the substance amount in moles, and $N_A$ is the Avogadro constant, which is equal to $6.02 \times 10^{23}$ particles per mole.

Since bromine is a diatomic molecule, Br$_2$, the number of molecules in 0.3 moles of bromine is:

$$N_{Br_2} = 0.3 \cdot 6.02 \times 10^{23} = 1.81 \times 10^{23}$$

The number of atoms in 0.3 moles of bromine is twice the number of molecules, since each molecule contains two atoms:

$$N_{Br} = 2 \cdot N_{Br_2} = 2 \cdot 1.81 \times 10^{23} = 3.62 \times 10^{23}$$

Therefore, the answer is:

0.3 moles of bromine contain 1.81 x 10^23 molecules and 3.62 x 10^23 atoms of bromine.

You can find more information about this topic on [this website](https://subject.com.ua/lesson/chemistry/8klas/5.html) or [this presentation](https://naurok.com.ua/prezentaciya-kilkist-rechovini-mol---odinicya-kilkosti-rechovini-stala-avogadro-217093.html).