Question

Сколько грамм оксида кремния необходимо для взаимодействия с 6,4 г гидроксида натрия?

Answer 1

Ответ:

≈3,15г

Объяснение:

X 6,4г

SiO2 + 2NaOH = Na2SiO3 + H2O

60г/моль 122г/моль

X= 60г/моль×6,4г

———————— ≈ 3,15г

122г/моль

Должно быть правильно. Извиняюсь, если неправильно

Answer 2

Calculating the Amount of Silicon Dioxide Needed to React with Sodium Hydroxide

To calculate the amount of silicon dioxide (SiO2) needed to react with 6.4 grams of sodium hydroxide (NaOH), we can use the balanced chemical equation for the reaction between silicon dioxide and sodium hydroxide:

SiO2 + 2NaOH → Na2SiO3 + H2O

From the balanced equation, we can see that 1 mole of SiO2 reacts with 2 moles of NaOH.

Step 1: Convert Sodium Hydroxide to Moles

First, we need to convert the mass of sodium hydroxide to moles. The molar mass of NaOH is approximately 40 g/mol.

Using the formula: moles = mass / molar mass

We can calculate the moles of NaOH: moles = 6.4 g / 40 g/mol = 0.16 moles

Step 2: Determine the Stoichiometry of the Reaction

From the balanced chemical equation, we know that 1 mole of SiO2 reacts with 2 moles of NaOH.

Step 3: Calculate the Amount of Silicon Dioxide Needed

Since 1 mole of SiO2 reacts with 2 moles of NaOH, the moles of SiO2 needed can be calculated using the stoichiometry of the reaction.

moles of SiO2 = moles of NaOH / 2 = 0.16 moles / 2 = 0.08 moles

Step 4: Convert Moles to Grams

Finally, we can convert the moles of SiO2 to grams using the molar mass of SiO2. The molar mass of SiO2 is approximately 60 g/mol.

Using the formula: mass = moles × molar mass

We can calculate the mass of SiO2 needed: mass = 0.08 moles × 60 g/mol = 4.8 grams

Therefore, approximately 4.8 grams of silicon dioxide (SiO2) are needed to react with 6.4 grams of sodium hydroxide (NaOH).

I hope this helps! If you have any further questions, feel free to ask.