Question

Перетворіть схеми реакцій на хімічні рівняння, а саме урівняйте:1) FeO + О2→Fe2O3;2) SiH4 + O2→SiO2 + H2O;3) Mn2O3 + O2→MnO2;4) NH3 + O2→N2 + H2O.

Answer 1

Відповідь:

1. Перетворіть схеми реакцій на хімічні рівняння, а саме урівняйте:

1) 4FeO+О2=2Fe2O3

2) SiH4+2O2=SiO2+2H2O

3) 2Mn2O3+O2=4MnO2

4) 4NH3+3O2=2N2+6H2O

Answer 2

Reaction Equations:

1) FeO + O2 → Fe2O3 2) SiH4 + O2 → SiO2 + H2O 3) Mn2O3 + O2 → MnO2 4) NH3 + O2 → N2 + H2O

Explanation:

1) The reaction between FeO (iron(II) oxide) and O2 (oxygen) forms Fe2O3 (iron(III) oxide). To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

FeO + O2 → Fe2O3

To balance the equation, we can start by balancing the oxygen atoms. There are 2 oxygen atoms on the left side and 3 oxygen atoms on the right side. To balance them, we can multiply FeO by 3 and O2 by 2:

3FeO + 2O2 → Fe2O3

Now, let's check the balance of iron atoms. There are 3 iron atoms on the left side and 2 iron atoms on the right side. To balance them, we can multiply Fe2O3 by 3:

3FeO + 2O2 → 3Fe2O3

The equation is now balanced with 3 FeO molecules reacting with 2 O2 molecules to produce 3 Fe2O3 molecules.

2) The reaction between SiH4 (silane) and O2 (oxygen) forms SiO2 (silicon dioxide) and H2O (water). To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

SiH4 + O2 → SiO2 + H2O

To balance the equation, we can start by balancing the oxygen atoms. There are 2 oxygen atoms on the left side and 3 oxygen atoms on the right side. To balance them, we can multiply O2 by 3:

SiH4 + 3O2 → SiO2 + H2O

Now, let's check the balance of silicon atoms. There is 1 silicon atom on the left side and 1 silicon atom on the right side. The silicon atoms are already balanced.

Finally, let's check the balance of hydrogen atoms. There are 4 hydrogen atoms on the left side and 2 hydrogen