Question

4.Какой объем кислорода (н. у.) потребуется для полного сгорания 6,72 л ,пропана C3H8(н. у) 5. При сжигании сероводорода pH2S истрачено 6л кислорода. Определите объем (л) образовавшегося оксида серы (4) (диоксида серы) ПОМОГИТЕ ПОЖАЛУЙСТА, БЕЗ СПАМА!!! ЭТО СРОЧНО!! ​

Answer 1

Задача 4

Дано:

V(C3H8)= 6,72 л

Найти:

V(O2)-?

Решение:

C3H8+5O2=3CO2+4H2O

n(C3H8)=V/Vm= 6,72 л:22,4 л/моль= 0,3 моль

n(C3H8)=n(O2)= 1,5 моль

V(O2)=n*Vm= 1,5 моль*22,4 л/моль= 33,6 л

Ответ: V(O2)+ 33,6 л

Задача 5

Дано:

V(O2)= 6 л

Найти:

V(SO2)-?

Решение:

2H2S+3O2=2SO2+2H2O

n(O2)=V/Vm= 6 л :22,4 л/моль= 0,3 моль

n(O2)=n(SO2)=0,2 моль

V(SO2)= n*Vm= 0,2 моль*22,4 л/моль=4,48 л

Ответ: V(SO2) = 4,48 л

Answer 2

Calculation of Oxygen Required for Complete Combustion of Propane (C3H8)

To calculate the volume of oxygen required for the complete combustion of propane (C3H8), we need to consider the balanced chemical equation for the combustion reaction:

C3H8 + 5O2 → 3CO2 + 4H2O

From the balanced equation, we can see that 1 mole of propane (C3H8) reacts with 5 moles of oxygen (O2) to produce 3 moles of carbon dioxide (CO2) and 4 moles of water (H2O).

To find the volume of oxygen required, we need to convert the given volume of propane (6.72 L) to moles using the ideal gas law:

PV = nRT

Where: P = pressure (assume constant) V = volume of gas (6.72 L) n = number of moles of gas (to be determined) R = ideal gas constant T = temperature (assume constant)

Since the pressure and temperature are assumed constant, we can rearrange the equation to solve for the number of moles:

n = PV / RT

Now, we can calculate the number of moles of propane:

n(C3H8) = (6.72 L) / (R * T)

Next, we can use the stoichiometry of the balanced equation to determine the number of moles of oxygen required. From the balanced equation, we know that 1 mole of propane reacts with 5 moles of oxygen. Therefore, the number of moles of oxygen required is:

n(O2) = 5 * n(C3H8)

Finally, we can convert the number of moles of oxygen to volume using the ideal gas law:

V(O2) = n(O2) * (R * T) / P

Now, let's calculate the volume of oxygen required for the complete combustion of 6.72 L of propane.

Calculation:

Given: Volume of propane (C3H8) = 6.72 L

Assuming constant pressure (P) and temperature (T), we can use the ideal gas law to calculate the number of moles of propane:

n(C3H8) = (6.72 L) / (R * T)

Next, we can calculate the number of moles of oxygen required:

n(O2) = 5 * n(C3H8)

Finally, we can convert the number of moles of oxygen to volume using the ideal gas law:

V(O2) = n(O2) * (R * T) / P

Please note that the values of the ideal gas constant (R) and temperature (T) need to be provided in order to perform the calculations accurately.