Question

Під час взаємодії алюмінію з сульфатною кислотою виділилося 33,6 л водню. Яка маса алюмінію та сульфатної кислоти вступила у реакцію?

Answer 1

Кислота равна к кислоте это правильно

Answer 2

Reaction of Aluminum with Sulfuric Acid

When aluminum reacts with sulfuric acid, hydrogen gas is produced. The balanced chemical equation for this reaction is:

2Al + 3H2SO4 → Al2(SO4)3 + 3H2

From the given information that 33.6 L of hydrogen gas was produced, we can calculate the mass of aluminum and sulfuric acid that reacted.

Calculating the Mass of Aluminum and Sulfuric Acid

To calculate the mass of aluminum and sulfuric acid that reacted, we can use the ideal gas law and molar mass of hydrogen gas.

The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol. Given that 33.6 L of hydrogen gas was produced, we can calculate the number of moles of hydrogen gas using the equation:

n = V / Vm

Where: - n is the number of moles - V is the volume of the gas - Vm is the molar volume of the gas at STP

Using the molar ratio from the balanced chemical equation, we can then determine the number of moles of aluminum and sulfuric acid that reacted.

Conclusion

By using the molar volume of a gas at STP and the balanced chemical equation for the reaction of aluminum with sulfuric acid, we can calculate the mass of aluminum and sulfuric acid that reacted to produce 33.6 L of hydrogen gas.