Question

До 300 г води прилили 300 г розчину з масовою часткою нітратної кислоти 30%. Якою стала масова частка нітратної кислоти в отриманому розчині? ДОПОМОЖІТЬ БУДЬ ЛАСКА!!!!!ДАЮ 50 БАЛІВ​

Answer 1

15%

Объяснение:

находила масу розчину 3000 грн + 3000 грн + 6000 грн по формулі -W%=mp-ни/m рну*100%находимо масу речовини mp-ни=W*m рну/100%=30%*300/100%=90гр W%90/600*100%=15%

Answer 2

I can help you with your question.

The mass fraction of nitric acid in the obtained solution is 15%. Here is how to find it:

- The mass of the solution is the sum of the masses of water and the initial solution: $$m_{solution} = m_{water} + m_{initial} = 300 + 300 = 600 \text{ g}$$ - The mass of nitric acid is the product of the mass of the initial solution and its mass fraction: $$m_{nitric} = m_{initial} \times w_{initial} = 300 \times 0.30 = 90 \text{ g}$$ - The mass fraction of nitric acid in the obtained solution is the ratio of the mass of nitric acid to the mass of the solution: $$w_{obtained} = \frac{m_{nitric}}{m_{solution}} = \frac{90}{600} = 0.15$$

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