Question

11. Складіть рівняння реакцій за схемою НСНО —> СН3ОН —> СН3СООСН3. Запишіть суму коефіцієнтів у обох записаних рівняннях.

Answer 1

Ответ:

HCHO + H2 = CH3OH

CH3OH + CH3COOH → CH3COOCH3 + H2O

Answer 2

Equation of the Reaction:

The reaction scheme you provided is as follows: NSNO -> CH3OH -> CH3COOCH3

To write the balanced equation for this reaction, we need to determine the coefficients of each compound. Let's break down the reaction step by step:

1. NSNO -> CH3OH: The reaction involves the conversion of NSNO to CH3OH. To balance this equation, we need to ensure that the number of atoms on both sides of the equation is equal. Since NSNO contains one nitrogen (N) atom and one sulfur (S) atom, and CH3OH contains one carbon (C) atom, four hydrogen (H) atoms, and one oxygen (O) atom, the balanced equation is:

NSNO -> CH3OH

2. CH3OH -> CH3COOCH3: The reaction involves the conversion of CH3OH to CH3COOCH3. Again, we need to balance the equation by ensuring that the number of atoms on both sides is equal. CH3OH contains one carbon (C) atom, four hydrogen (H) atoms, and one oxygen (O) atom, while CH3COOCH3 contains three carbon (C) atoms, eight hydrogen (H) atoms, and three oxygen (O) atoms. The balanced equation is:

CH3OH -> CH3COOCH3

Coefficients in the Equations:

Now, let's determine the coefficients in both equations:

1. NSNO -> CH3OH: Since there is only one NSNO molecule on the left side, the coefficient is 1. Similarly, there is only one CH3OH molecule on the right side, so the coefficient is also 1.

Therefore, the balanced equation is:

NSNO -> CH3OH

2. CH3OH -> CH3COOCH3: Again, there is only one CH3OH molecule on the left side, so the coefficient is 1. On the right side, there is only one CH3COOCH3 molecule, so the coefficient is also 1.

Therefore, the balanced equation is:

CH3OH -> CH3COOCH3

In summary, the balanced equations for the given reaction scheme are:

1. NSNO -> CH3OH 2. CH3OH -> CH3COOCH3

The coefficients in both equations are 1.