Question

СРОЧНОООО!!!!!! Який об’єм водню виділиться при взаємодії 1,2 г Mg та 5,5г H2SO4?

Answer 1

Ответ:

1.12л

Объяснение:

счет за нестачей,за надлишком считать нельзя,тобиш считаем за магнием,соответсвенно вот ответ на фото.

Answer 2

Reaction Calculation

To calculate the volume of hydrogen gas produced when 1.2g of Mg reacts with 5.5g of H2SO4, we can start by writing and balancing the chemical equation for the reaction between magnesium and sulfuric acid:

Mg + H2SO4 → MgSO4 + H2

Now, let's calculate the moles of each reactant using their respective molar masses.

Molar Mass Calculation

The molar mass of Mg is 24.305 g/mol, and the molar mass of H2SO4 is 98.079 g/mol.

- Moles of Mg = Mass of Mg / Molar mass of Mg - Moles of H2SO4 = Mass of H2SO4 / Molar mass of H2SO4

Limiting Reactant

Next, we determine the limiting reactant to find out which reactant will be completely consumed and hence determine the amount of hydrogen gas produced.

Stoichiometry Calculation

Using the balanced chemical equation, we can then calculate the moles of hydrogen gas produced and convert it to volume using the ideal gas law if the conditions are provided.

Let's proceed with these calculations to find the volume of hydrogen gas produced.