Question

P2O5 -> Na3PO4 -> NaH2PO4 -> Na2HPO4 -> Na3PO4 -> Ag3PO4

Answer 1

P2O5->Na3PO4->NaH2PO4->Na2HPO4->Na3PO4->Ag3PO4

P2O5+6 NaOH = 2 Na3PO4+3 H2O

Na3PO4+2 H3PO4 = 3 NaH2PO4

NaH2PO4 + NaOH = Na2HPO4 + H2O

Na2HPO4 + NaOH = Na3PO4 + H2O

Na3PO4 + 3AgF = 3NaF + Ag3PO4

Answer 2

The given sequence describes a series of chemical reactions involving the compound P2O5 (diphosphorus pentoxide) and various sodium phosphate compounds, ultimately leading to the formation of silver phosphate (Ag3PO4). Let's break down each step:

1. P2O5: This is diphosphorus pentoxide, a compound composed of two phosphorus atoms and five oxygen atoms.

2. Na3PO4: This represents sodium phosphate, where three sodium atoms (Na) combine with one phosphate ion (PO4). This reaction typically occurs by treating P2O5 with sodium oxide (Na2O).

3. NaH2PO4: Here, sodium dihydrogen phosphate is formed by reacting sodium phosphate (Na3PO4) with an acid or water. One of the sodium ions (Na+) is replaced by a hydrogen ion (H+) to form NaH2PO4.

4. Na2HPO4: In this step, sodium hydrogen phosphate is obtained by treating NaH2PO4 with a base or by adjusting the pH of the solution. One of the hydrogen ions (H+) is replaced by a sodium ion (Na+) to form Na2HPO4.

5. Na3PO4: This step involves the reformation of sodium phosphate. By adjusting the pH or adding a sodium hydroxide solution (NaOH) to Na2HPO4, one of the hydrogen ions (H+) is replaced by a sodium ion (Na+) to yield Na3PO4.

6. Ag3PO4: Finally, silver phosphate is formed by reacting Na3PO4 with a silver nitrate solution (AgNO3). The silver ions (Ag+) in AgNO3 replace the sodium ions (Na+) in Na3PO4, resulting in the formation of Ag3PO4.

It's important to note that the specific conditions, concentrations, and reaction conditions may vary depending on the experimental setup or intended purpose.