Question

Осуществить цепочку превращений:Ba → BaO → Ba(OH)2 → BaBr2 → AgBr​

Answer 1

Ответ есть на фотографии

Answer 2

Ответ:

2Ba+O2=2BaO;

BaO+H2O=Ba(OH)2;

Ba(OH)2+2HBr=BaBr2+H2;

BaBr2+2AgNO3=2AgBr+Ba(NO3)2

Объяснение:

Answer 3

Ba → BaO → Ba(OH)2 → BaBr2 → AgBr

Ba (Barium) reacts with oxygen (O) to form Barium oxide (BaO).

2 Ba + O2 → 2 BaO

Barium oxide (BaO) reacts with water (H2O) to form Barium hydroxide (Ba(OH)2).

BaO + H2O → Ba(OH)2

Barium hydroxide (Ba(OH)2) reacts with hydrobromic acid (HBr) to form Barium bromide (BaBr2).

Ba(OH)2 + 2 HBr → BaBr2 + 2 H2O

Barium bromide (BaBr2) reacts with silver nitrate (AgNO3) to form Silver bromide (AgBr) and Barium nitrate (Ba(NO3)2).

BaBr2 + 2 AgNO3 → 2 AgBr + Ba(NO3)2

The final result is AgBr (Silver bromide).