Question

KMnO4+KNO2+H2O->MnO2+KNO3+KOH

Answer 1

KMnO4+KNO2+H2O->MnO2+KNO3+KOH
окислитель Mn+7(+3е)->Mn+4           2
восстановитель N+3(-2e)->N+5          3
2KMnO4+3KNO2+H2O->2MnO2+3KNO3+2KOH

Answer 2

The equation you provided represents a chemical reaction involving the substances potassium permanganate (KMnO4), potassium nitrite (KNO2), and water (H2O) on the left side of the equation, and the products manganese dioxide (MnO2), potassium nitrate (KNO3), and potassium hydroxide (KOH) on the right side of the equation.

The balanced equation for this reaction is as follows:

2 KMnO4 + 3 KNO2 + 4 H2O -> 2 MnO2 + 3 KNO3 + 4 KOH

In this reaction, two molecules of potassium permanganate, three molecules of potassium nitrite, and four molecules of water react to form two molecules of manganese dioxide, three molecules of potassium nitrate, and four molecules of potassium hydroxide. The equation is balanced with respect to both the number of atoms and the charges.