
Вопрос задан 06.05.2023 в 07:47.
Предмет Химия.
Спрашивает Жданов Игорь.
ch3-ch2-ch2-br ---> x1 (kmno4, h2o, t°) ---> ch3cook


Ответы на вопрос

Отвечает Волжина Алина.
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.
The reaction involves oxidation of the alkyl bromide to a carboxylic acid, and subsequent conversion of the carboxylic acid to a ketone using a base.
The overall reaction is:
CH3-CH2-CH2-Br + KMnO4 + H2O → CH3-CO2H + MnO2 + HBr
CH3-CO2H + NaOH → CH3-COOK + H2O
The first step involves the use of potassium permanganate (KMnO4) and water, which oxidizes the alkyl bromide to a carboxylic acid. The reaction occurs in acidic medium, and produces manganese dioxide (MnO2) and hydrogen bromide (HBr) as byproducts.
In the second step, the carboxylic acid is treated with sodium hydroxide (NaOH), which deprotonates the acid to form a carboxylate anion. The anion then reacts with the base to form the corresponding ketone (CH3-COOK) and water (H2O).
Overall, this reaction transforms an alkyl bromide into a ketone through a two-step oxidation and deprotonation process.
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The overall reaction is:
CH3-CH2-CH2-Br + KMnO4 + H2O → CH3-CO2H + MnO2 + HBr
CH3-CO2H + NaOH → CH3-COOK + H2O
The first step involves the use of potassium permanganate (KMnO4) and water, which oxidizes the alkyl bromide to a carboxylic acid. The reaction occurs in acidic medium, and produces manganese dioxide (MnO2) and hydrogen bromide (HBr) as byproducts.
In the second step, the carboxylic acid is treated with sodium hydroxide (NaOH), which deprotonates the acid to form a carboxylate anion. The anion then reacts with the base to form the corresponding ketone (CH3-COOK) and water (H2O).
Overall, this reaction transforms an alkyl bromide into a ketone through a two-step oxidation and deprotonation process.


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